> From: "Alexander Tsonev" <[EMAIL PROTECTED]>
>
> Hello,
> I would ask you a question about date type
> if I have a variable from date type ($newdate) such as 2003-02-17
> how can I separate $newdate into 3 different variables? I want to create
> such variables:
> $day=17
> $month=2
> $year=2003
> I searched a lot, but I didn't find how to do this.
> I'll be very happy if someone helps!
>
list($year, $month, $day) = explode("-", $newdate);
--
Lowell Allen
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