You could do it reading back to front the way you propose but I think it will work much better in a proper for loop.
// the number of elements in the array. $num_lines = count($file); // the line we want to start the loop at. if ($num_lines > 10) $start_line = $num_lines - 10; else $start_line = 0; // loop through the array for ($i=$start_line; $i<$num_lines; $i++) { echo "Line #$i.\n"; //do your work here.. } Hope that helps. Also please don't spam the list. Check your email program make sure you're sending out only one copy. - Kevin ----- Original Message ----- From: "WebDev" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Thursday, March 06, 2003 3:24 PM Subject: [PHP] reading last -n lines array is emty How to grab the last -n lines from a data file and display the stored data Only the the last 10 line numbers coming back when I echo $i How do I get the list($adnr, $user, $date, $listed .... to catch the datafields datafile looks like 23|Werner|LastN|Street|etc|etc.|etc|||||| 24|Veronika|||| // code start $file = file("data/ads.data"); for ($i = count($file); $i > count($file) - 10; $i--) foreach($i as $line) { list($adnr, $user, $date, $listed, $hlong, $eins, $zwei, $drei, $vier, $usern, $locst, $locstaa, $locc, $funf, $sech, $email, $Url, $ClassCat, $ClassCat2, $Headstart, $Headend, $Descrip, $End1, $Endzwei, $End3, $Endvier, $Endfunf, $Endsech, $Endsieben, $Endacht, $Endne, $dreizwei, $dreidrei, $dreivier, $dreifunf, $dreisechs ) = split ("\|", $buffer); print " $i <a href=\"classifieds.cgi?session_key=&search_and_display_db_button=on&db_id=$a dnr&query=retrieval\" target=\"_blanko\">$Endzwei $End3</a> <br>"; }; // Code end -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php