While Unix provides a crypt() function, it does NOT provide a
decrypt() function. The designers of crypt() functions want to
make the retrieval of the plain text password difficult - at least
that is what they want. So the plain text password is, in
theory, not possible to compute, except by trial and error. By
trying out dictionary words, dates, names of people, etc, the
crack program attempts to guess the password, and it sometimes
gets lucky and guesses the password correctly.
If you are able to write a decrypt() function that works, then
you will be a millionaire, since you would have defeated all those
fancy mathematical theory used in DES, RSA, Blowfish, etc
and you will render SSL-based infrastructure like Verisign, Thawte
and others useless.
Pablo Manalastas
***
Roger Filomeno <[EMAIL PROTECTED]> wrote: My guess is its a ProFTPd password?
Then its encrypted using cryp(), a standard linux encryption function. John
should be able to help you.
On Thu, May 1, 2008 at 5:30 AM, Iris Lames <[EMAIL PROTECTED]> wrote:
Hi Guys,
Please help me decrypt password into readable texts.
I have a sample here:
dn: uid=some.user,ou=people,dc=mydomain,dc=com
userPassword:: VmVRdWFrczE=
Please tell me what tool you used in order to decrypt it. (Promise, I'll use
this in good ways).
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