I already solved the problem. Anyhow, I'm not aware of tables/dsv addon nor
the Package Manager. Will you be so kind to explain these subjects to me?
----- Original Message -----
From: "Ric Sherlock" <tikk...@gmail.com>
To: "Programming JForum" <programm...@jsoftware.com>
Sent: Monday, December 23, 2013 8:57 PM
Subject: Re: [Jprogramming] A little question
If you are trying to numerize any items in a boxed table that can be
numerized (rather than understand why your verb isn't working) then the
makenum verb from the tables/dsv addon may be useful:
Install 'tables/dsv' addon using package manager (if not already
installed). Then:
require 'tables/dsv'
datatype each makenum_pdsv_ 'ALPHA';'266239';'1'
┌───────┬───────┬───────┐
│literal│integer│boolean│
└───────┴───────┴───────┘
On Tue, Dec 24, 2013 at 9:33 AM, Devon McCormick <devon...@gmail.com>
wrote:
You have two arguments on the left but three on the right: that's why
it's
a length error. As Henry mentioned, something like "(<1 2) numerize each
t" effectively fixes this by making the left argument a scalar, which can
be applied to each element on the right (under disclose).
On Mon, Dec 23, 2013 at 3:26 PM, Henry Rich <henryhr...@nc.rr.com> wrote:
> Try
> 1 2&numerize each t
> or
> (<1 2) numerize each t
>
> Henry Rich
>
>
> On 12/23/2013 11:07 AM, Ricardo Forno wrote:
>
>> Thanks. But it now fails with length error when calling numerize with
>> a
>> vector left argument:
>>
>> numerize =: 13 : '(".&.>x{y)x}y'
>> .............................................
>> z =: t =. cutopen each ,&' ' each t
>> t =. 1 2 numerize each t
>> where z is something like:
>> ┌────────────────┬───────────────┬───────────────┐
>> │┌─────┬──────┬─┐│┌────┬──────┬─┐│┌──────┬────┬─┐│
>> ││ALPHA│266239│1│││BETA│270271│1│││BROKEN│9288│2││
>> │└─────┴──────┴─┘│└────┴──────┴─┘│└──────┴────┴─┘│
>> └────────────────┴───────────────┴───────────────┘
>> |length error: readpars
>> | t=.1 2 numerize each t
>>
>> ----- Original Message ----- From: "Devon McCormick" <
devon...@gmail.com>
>> To: "J-programming forum" <programm...@jsoftware.com>
>> Sent: Monday, December 23, 2013 12:11 AM
>> Subject: Re: [Jprogramming] A little question
>>
>>
>> If you break down what's happening inside the function with your
example:
>>> 1 2{arg
>>> +------+-+
>>> |266239|1|
>>> +------+-+
>>> >1 2{arg
>>> 266239
>>> 1
>>> ".>1 2{arg
>>> 266239 1
>>>
>>> So this vector gets boxed and put into both places. If you allow for
>>> multiple elements in "x", you might do something like this:
>>>
>>> (".&.>1 2{arg) (1 2)}arg
>>> +-----+------+-++
>>> |ALPHA|266239|1||
>>> +-----+------+-++
>>>
>>> So,
>>>
>>> numerize =: 13 : '(".&.>x{y)(x)}y'
>>>
>>> ([: {. 0 $ ]) &.> 1 2 numerize arg NB. Show 0 for numeric, ' ' for
>>> character arguments.
>>> +-+-+-+-+
>>> | |0|0| |
>>> +-+-+-+-+
>>>
>>>
>>> On Sun, Dec 22, 2013 at 3:22 PM, Ricardo Forno
>>> <ricardofo...@tutopia.com>wrote:
>>>
>>> I have this little function:
>>>> numerize =: 13 : '(<".x{>y)x}y'
>>>> It makes numeric the contents of the xth box of the y argument. For
>>>> example, let b:
>>>> b
>>>> ┌─────┬──────┬─┐
>>>> │ALPHA│266239│1│
>>>> └─────┴──────┴─┘
>>>>
>>>> 1 numerize b makes numeric the middle box.
>>>> Why does it not work with the last two elements of b, namely:
>>>> 1 2 numerize b
>>>> but instead inserts a 2.element vector in each of the boxes 1 and 2?
>>>> Thanks.
>>>>
>>>> ----------------------------------------------------------------------
>>>> For information about J forums see
http://www.jsoftware.com/forums.htm
>>>>
>>>
>>>
>>>
>>>
>>> --
>>> Devon McCormick, CFA
>>> ----------------------------------------------------------------------
>>> For information about J forums see
>>> http://www.jsoftware.com/forums.htm
>>>
>>
>> ----------------------------------------------------------------------
>> For information about J forums see http://www.jsoftware.com/forums.htm
>>
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
--
Devon McCormick, CFA
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