First tip: Rather than using the Dictionary, use NuVoc.
Second tip: learn how to use the dissect tool.
Third tip: understand what "the rank of a verb" means.
I can't figure out your basic wrongthink here but let me point out that
j. is a verb that joins two nouns to make a complex noun, while the j in
1j2 is part of the constant notation.
You do NOT need to update J.
Other comments below.
Henry Rich
On 6/30/2017 11:14 PM, Lawrence Wickert wrote:
Hello, I am a old EE still trying to learn. I am a real beginner having no
end of problems with specifying complex numbers. I am using j64-804 on ubuntu
12.04. I am either doing something really stupid or I need to update to 806.
Updating anything gives me heartburn or worse so I hope it is just my
misunderstanding of basic principles. Although I have a bad habit of RTFM as a
last resort I have tried the Dictionary to no avail. I appreciate any guidance.
0j(2^0.5)%2
|ill-formed number
0j((2^0.5)%2)
|ill-formed number
j.(2^0.5)%2
0j0.707107
NB. Eureaka, OK, I get it!
NB. But wait, not so fast:
1j.(2^0.5)%2
|ill-formed number
NB. No
1j(2^0.5)%2
|ill-formed number
NB. Still No
1+j.(2^0.5)%2
1j0.707107
NB. This works!
The principle is: any word that starts with (numeric or _)must be a
valid number.
1j was not a valid number.
Let's try to do something with it:
k=:(0 1+j.(2^0.5)%2 3 4 0 5)
|length error
| k=:(0 1 +j.(2^0.5)%2 3 4 0 5)
You are adding a list of 2 numbers to a list of 5 numbers.
NB. Maybe parantheses will help:
k=:(0 (1+j.(2^0.5)%2) 3 4 0 5)
|syntax error
| k=:( 0(1+j.(2^0.5)%2)3 4 0 5)
You have
noun noun noun
which is illegal.
NB. This one has to work:
k=:(0 1j0.7071 3 4 0 5)
k
0 1j0.7071 3 4 0 5
NB. It does but it can't be the only way to do it.
NB. One last rry:
g=: 1+j.(2^0.5)%2
g
1j0.707107
NB. That's nice.
k=:(0 g 3 4 0 5)
|syntax error
| k=:( 0 g 3 4 0 5)
NB. This isn't nice.
You have noun noun noun which is illegal. Try
0 , g , 3 4 0 5
Lost in the high desert of New Mexico, Larry Wickert
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