Dear Raul,
thanks for your prompt answer, I hope I understand the logic at least somehow.
The first part is understood, you break the list of boxes and rebuild it
back.
The second question, by my fault, was misinterpreted.
I actually want to do the operation on each third box (where, by chance,
are big numbers).
So is something like the following the way how that should be done?
myword =: 3 : '(< 50000 -~ 2{::y) 2}y'
myword each ee
Thanks.
Ruda
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