That approach looks like it matches that description of what you want. Thanks,
-- Raul On Fri, Mar 20, 2020 at 11:10 AM Rudolf Sykora <[email protected]> wrote: > > Dear Raul, > > > thanks for your prompt answer, I hope I understand the logic at least somehow. > The first part is understood, you break the list of boxes and rebuild it > back. > > The second question, by my fault, was misinterpreted. > I actually want to do the operation on each third box (where, by chance, > are big numbers). > > So is something like the following the way how that should be done? > > myword =: 3 : '(< 50000 -~ 2{::y) 2}y' > myword each ee > > Thanks. > > Ruda > > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
