Here's how I would do it: 3++/\+:i.10 3 5 9 15 23 33 45 59 75 93
This preserves the 'missing' initial term of 3. If you don't want it, replace i.10 with >:i.10.
-E On Sat, 5 Mar 2022, 'Skip Cave' via Programming wrote:
I have this series: 5 9 15 23 33 .... 5+4 9 9+6 15 15+8 23 23+10 33 How can I use the power conjunction to generate this series? Is there a more concise method to generate this than the power conjunction? Skip Skip Cave Cave Consulting LLC ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
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