Ah, David beat me to it! :)
On Sat, 5 Mar 2022, Elijah Stone wrote:
Here's how I would do it:
3++/\+:i.10
3 5 9 15 23 33 45 59 75 93
This preserves the 'missing' initial term of 3. If you don't want it,
replace i.10 with >:i.10.
-E
On Sat, 5 Mar 2022, 'Skip Cave' via Programming wrote:
I have this series:
5 9 15 23 33 ....
5+4
9
9+6
15
15+8
23
23+10
33
How can I use the power conjunction to generate this series?
Is there a more concise method to generate this than the power conjunction?
Skip
Skip Cave
Cave Consulting LLC
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
