(1) Look at m`:0
(2)
v10 =. v0 , v1 , v2...
v11 =. v10, v11, ...
allv =. v10 , v11
Henry Rich
On 4/2/2022 1:42 PM, Devon McCormick wrote:
Hi,
I have a group of monadic verbs for which I want the concatenated result,
e.g.
foo0=: 3 : '0'
foo1=: 3 : '1'
foo2=: 3 : '2'
foo3=: 3 : '3'
allfoo=: foo0,foo1,foo2,foo3
allfoo ''
0 1 2 3
So *allfoo* does what I want. However, my actual set of verbs is longer
than this so I broke the assignment of *allfoo* into two pieces for
readability:
allfoo=: foo0,foo1
allfoo=: allfoo,foo2,foo3
allfoo
allfoo , foo2 , foo3
allfoo ''
|stack error: foo3
|allfoo[0]
I have inadvertently introduced infinite recursion. Clearly I'm missing
something thinking I can concatenate verbs like I can concatenate nouns.
This gives me a result that performs as expected but looks bad:
allfoo=: foo0,foo1
allfoo=: (allfoo f.),foo2,foo3
allfoo''
0 1 2 3
allfoo
(3 : (,'0') , 3 : (,'1')) , foo2 , foo3
Any suggestions on how to break the assignment into multiple lines?
Thanks,
Devon
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