want to draw attention to a bug in the jplayground using a variation of your script
https://jsoftware.github.io/j-playground/bin/html/emj.html#code=%20foo0%3D%3A%203%20%3A%20'0'%0D%0A%20%20foo1%3D%3A%203%20%3A%20'1'%0D%0A%20%20foo2%3D%3A%203%20%3A%20'2'%0D%0A%20%20foo3%3D%3A%203%20%3A%20'3'%0D%0A%20%20allfoo%3D%3A%20foo0%2Cfoo1%2Cfoo2%2Cfoo3%0D%0A%20%20allfoo%20''%0D%0A%20%20allfoo%3D%3A%20foo0%2Cfoo1%0D%0A%20%20allfoo%3D%3A%20allfoo%20f.%60%2C%60foo2%60%2C%60foo3%60%3A6%20%0D%0A%20%20allfoo allfoo does not return a value (verb) and resetting/refreshing playground is needed to get assignments to work. I don't think it is a bug though. scoped recursion is achieved through names. The use of f. to do what you intended (no parentheses needed, btw) is a good use of f. to easily "solve everything". another playground link, that provides an alternate solution allfoofinal=: allfoo,foo2,foo3 https://jsoftware.github.io/j-playground/bin/html/emj.html#code=c%20foo0%3D%3A%203%20%3A%20'0'%0D%0A%20%20foo1%3D%3A%203%20%3A%20'1'%0D%0A%20%20foo2%3D%3A%203%20%3A%20'2'%0D%0A%20%20foo3%3D%3A%203%20%3A%20'3'%0D%0A%20%20allfoo%3D%3A%20foo0%2Cfoo1%2Cfoo2%2Cfoo3%0D%0A%20%20allfoo%20''%0D%0A%20%20allfoo%3D%3A%20foo0%2Cfoo1%0D%0A%20%20allfoofinal%3D%3A%20allfoo%2Cfoo2%2Cfoo3%0D%0A%20%20allfoofinal On Saturday, April 2, 2022, 01:42:43 p.m. EDT, Devon McCormick <devon...@gmail.com> wrote: Hi, I have a group of monadic verbs for which I want the concatenated result, e.g. foo0=: 3 : '0' foo1=: 3 : '1' foo2=: 3 : '2' foo3=: 3 : '3' allfoo=: foo0,foo1,foo2,foo3 allfoo '' 0 1 2 3 So *allfoo* does what I want. However, my actual set of verbs is longer than this so I broke the assignment of *allfoo* into two pieces for readability: allfoo=: foo0,foo1 allfoo=: allfoo,foo2,foo3 allfoo allfoo , foo2 , foo3 allfoo '' |stack error: foo3 |allfoo[0] I have inadvertently introduced infinite recursion. Clearly I'm missing something thinking I can concatenate verbs like I can concatenate nouns. This gives me a result that performs as expected but looks bad: allfoo=: foo0,foo1 allfoo=: (allfoo f.),foo2,foo3 allfoo'' 0 1 2 3 allfoo (3 : (,'0') , 3 : (,'1')) , foo2 , foo3 Any suggestions on how to break the assignment into multiple lines? Thanks, Devon -- Devon McCormick, CFA Quantitative Consultant ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
