Please. I don't understand the rank stuff.
f1 6 f2@f3@f4@f5 7 14 NB. This gives the result I want.
2 4
1 1
6 f1@f2@f3@f4@f5 7 14 NB. but not this
2 2.83
0.5 0.354
6 f1@:f2@f3@f4@f5 7 14 NB. this is correct.
2 4
1 1
WHY is @: needed here and not everywhere?
6 f1@(f2@f3@f4@f5) 7 14 NB. This works
2 4
1 1
6 f1@(f2@f3)@f4@f5 7 14 NB. and this
2 4
1 1
The following definitions and explanations should not be necessary in order to
understand the problem, but just in case they are: The verb f5 is a dyad while
f4 f3 f2 and f1 are monads. f4 and f3 are hooks. f5 and f1 are forks.f2 is a
gerund.
f5
1 , ,:
6 f5 7 14
1 1
6 6
7 14
f4
% +/@{:
f4 6 f5 7 14
0.0476 0.0476
0.286 0.286
0.333 0.667
f3
,: -.
f3 f4 6 f5 7 14
0.0476 0.0476
0.286 0.286
0.333 0.667
0.952 0.952
0.714 0.714
0.667 0.333
f2
%~`*`:3"2
f2 f3 f4 6 f5 7 14
2 4
0.5 0.25
f1
}: , %:@*/
f1 f2 f3 f4 6 f5 7 14
2 4
1 1
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