You're passing a string constant to $$
"input[type=radio][name='type'][value=selectThis]")
'selectThis' will not be evaluated, as you seem to be expecting. Have a
loook at Tenplate to do what you want:
http://www.prototypejs.org/api/template
--
Jonathan Rosenberg
Founder & Executive Director
Tabby's Place
http://www.tabbysplace.org <http://www.tabbysplace.org/>
-----Original Message-----
From: prototype-scriptaculous@googlegroups.com
[mailto:prototype-scriptacul...@googlegroups.com] On Behalf Of Phil Petree
Sent: Saturday, September 25, 2010 7:46 AM
To: prototype-scriptaculous@googlegroups.com
Subject: [Proto-Scripty] Variables in $$() ?????
I've hit this in two seperate places and not exactly sure why...
(I think its the 18 hour days, 7 days a week... <g>)
If "value" is hard set with '3' the following works:
$$("input[type=radio][name='type'][value='3']")[0].writeAttribute("checked",
"checked");
However, if we use a variable (selectThis) and assign it "3" it does not
work.
var selectThis;
selectThis = '3';
$$("input[type=radio][name='type'][value=selectThis]")[0].writeAttribute("ch
ecked", "checked");
Type casting doesn't work either:
var selectThis;
selectThis = String('3');
$$("input[type=radio][name='type'][value=selectThis]")[0].writeAttribute("ch
ecked", "checked");
I'm having the same problem here too (compare o.value== 'GA' and the select
gets set to GA):
selectThis = 'GA'
$$('select#ajstate option').each(function(o){
if(o.value==selectThis){o.selected = true;$break;}
});
What am I missing here?
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