On 2012-04-16 15:26, Antidot SAS wrote: > A quick question for you, here is the code: > $tt=regsubst("test","^(.*)->(.*)",'\2') > > Doesn't return: undef or nil, it does return: "test"
As expected and intended. > Niether does $tt=regsubst("test","^(.?)->(.*)",'\2') > or $tt=regsubst("test","^(.+?)->(.*)",'\2'). > > Is there a way to return undef if the string doesn't include '->something' ? Perhaps something like this: $x = 'test' $temp = regsubst($x, '^(.*)->(.*)', '\2') if $temp == $x { # No substitution done, must mean there is no "->" in $x $tt = undef } else { $tt = $temp } Or perhaps this: $tt = regsubst($x, '^(.*)->(.*)|.*', '\2') It will however give you the empty string (""), not undef, if there is no "->" in the string. /Bellman -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To post to this group, send email to puppet-users@googlegroups.com. To unsubscribe from this group, send email to puppet-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/puppet-users?hl=en.