Thx for the reply it helps.
But how come the \2 returns something that I never asked?
On Mon, Apr 16, 2012 at 3:47 PM, Thomas Bellman <bell...@nsc.liu.se> wrote:
> On 2012-04-16 15:26, Antidot SAS wrote:
>
> > A quick question for you, here is the code:
> > $tt=regsubst("test","^(.*)->(.*)",'\2')
> >
> > Doesn't return: undef or nil, it does return: "test"
>
> As expected and intended.
>
> > Niether does $tt=regsubst("test","^(.?)->(.*)",'\2')
> > or $tt=regsubst("test","^(.+?)->(.*)",'\2').
> >
> > Is there a way to return undef if the string doesn't include
> '->something' ?
>
> Perhaps something like this:
>
> $x = 'test'
> $temp = regsubst($x, '^(.*)->(.*)', '\2')
> if $temp == $x {
> # No substitution done, must mean there is no "->" in $x
> $tt = undef
> } else {
> $tt = $temp
> }
>
> Or perhaps this:
>
> $tt = regsubst($x, '^(.*)->(.*)|.*', '\2')
>
> It will however give you the empty string (""), not undef, if there is
> no "->" in the string.
>
>
> /Bellman
>
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