I remember having issues at one point with references as I was confused at why changes to one array changed the other. My work-around has simply been: x = [1, 2, 3] y = x[:]
Nice to see there are other methods though. On Wed, Mar 12, 2008 at 9:04 PM, Greg Ewing <[EMAIL PROTECTED]> wrote: > Ian Mallett wrote: > > > If I have something like: > > x = [1,2,3,4,5,6] > > y = x > > then changes to y change x. > > That's a rather loose way of talking about it. What's > happening is that x and y refer to the same object, > so any changes made to that object will be seen through > both x and y. > > The important things to understand are: > > (1) Python variables always contain references to objects, > not the objects themselves. > > (2) The '=' operation is always reference assignment. > It never copies any objects. > > > y = [x[0],x[1],x[2],x[3],x[4],x[5]] > > ...which doesn't change x when y is changed. > > Also > > (3) The [...] notation always constructs a new list > object. > > -- > Greg > > -- This, from Jach. How many programmers does it take to change a light bulb? None. It's a hardware problem. How many Microsoft programmers does it take to change a light bulb? None. Microsoft just declared darkness as the newest innovation in cutting-edge technology.
