Hmm, ok that sounds possible.
I tried this:
player = pyglet.media.Player() # init player
player.play() # let player play
def play_sound(name):
path = name + ".wav"
source = pyglet.media.load(path, streaming=False)
print "Playing sound!", name
player.queue(source)
This works for exactly one sound. The second call of the function brings
the print-statement but no sound.
Did I missunderstand something?
I tried also a player.play() after adding the source to the queue - same
result.
Thanks,
Sebastian
Am Dienstag, 17. Februar 2015 17:05:43 UTC+1 schrieb Rob:
>
> I suspect a new player is created for every sound. The player registers a
> stream. As long as the player is not destroyed, the stream remains active.
> Try if you can control a single player:
> http://pyglet.readthedocs.org/en/pyglet-1.2-maintenance/programming_guide/media.html
>
> Rob
>
> Op dinsdag 17 februari 2015 11:36:41 UTC+1 schreef Sebastian Meyer:
>>
>> Hi there!
>>
>> I have a small project which uses pyQt for the GUI. It is OS-independent
>> and I want to add some sound-notifacation on it.
>> After some searching I decided the best solution to have OS-independent
>> sound-output is using pyglet for it. And it works great.
>>
>> But there is one problem:
>> I'm using Linux with KDE and the mixer for adjusting the volume-level
>> shows a modulator for every program that plays sound.
>> But for my programm it shows a new regulator everytime I use pyglet to
>> play a sound. So after the first sound, there appears one, after the second
>> there are two and so on.
>>
>> I'm playing the sound as descripted here:
>> http://www.pyglet.org/doc/programming_guide/playing_sounds_and_music.html
>>
>> Any ideas?
>>
>> Cheers
>> Sebastian
>>
>
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