Hi Rob,
Thank you very much for your response. I have attached a simplified version
of the code and, yes, here I clearly see that more than one event arrives
in an iteration of the loop.
How can I register the observers only once each iteration?
I have not found any example that process the events like this, could you
tell me where I could find some?
Thank you,
jl
El dimecres, 25 febrer de 2015 19:12:24 UTC+1, Rob va escriure:
>
> Hi,
>
> I just took a short look. As I see you call my_dispatch_events() in your
> event loop. Each time it registers a new set of event observers that all
> use the same event object to store the results.
>
> The problem here is that it is possible that more than 1 event arrives in
> 1 iteration of the loop. In that case the event object is overwritten with
> the last event. Also it is not necessary to keep registering new observers.
> This will probably in the end cause some kind of memory and resource leak.
>
> It is better to have the observers registered only once and then have them
> store each event in a Queue (or list). Then in your loop process the
> contents of the Queue before going to the next iteration.
>
> Rob
>
> Op woensdag 25 februari 2015 17:33:25 UTC+1 schreef Jose Luis Da:
>>
>> Hi all,
>>
>> I am using pyglet to develop a series of visual stimuli. I have some
>> problems with my code, could you help me understand what I am doing wrong?
>>
>> I have attached a part of the code I am using, the main file is called
>> "150121_Plaid_v19", and "rlabs_libutils" is a library of some functions,
>> one of which I will explain next.
>> In lines 190 - 258 I have the stimulus loop (or game loop) and for each
>> iteration I need to retrieve the subject's input and save it in an array.
>> In order to do that, I use the function 'my_dispatch_events', which I call
>> in line 204 with the pyglet window and an instance of a class called
>> LastEvent() that I defined.
>>
>> With this method, I lose some of the data. Could you help me understand
>> what would be a good method of retrieving input events and saving them for
>> each iteration of the game loop, while using as few global variables as
>> possible (I would like to keep the pyglet window instance as a local
>> variable)?.
>>
>> Thank you very much for your attention,
>> jl
>>
>
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import pyglet
class mypygletwindow:
def __init__(self):
self.winHandle = pyglet.window.Window()
self.winHandle.on_mouse_press = self._onPygletMousePress
self.winHandle.on_mouse_release = self._onPygletMouseRelease
self.winHandle.on_key_press = self._onPygletKeyPress
self.winHandle.on_key_release = self._onPygletKeyRelease
self.winHandle.getevent = self.getevent
self.lastevent = {}
def _onPygletMousePress(self, x,y,button,modifiers):
print 'press', button, (x,y)
self.lastevent = {'type':'MOUSEDOWN', 'button': button, 'pos': (x,y)}
def _onPygletMouseRelease(self,x,y, button, modifiers):
print 'release', button, (x,y)
self.lastevent = {'type':'MOUSEUP', 'button': button, 'pos': (x,y)}
def _onPygletKeyPress(self, symbol, modifiers):
print 'press', symbol, modifiers
self.lastevent = {'type':'KEYDOWN', 'symbol': symbol}
def _onPygletKeyRelease(self, symbol, modifiers):
print 'release', symbol, modifiers
self.lastevent = {'type':'KEYUP', 'symbol': symbol}
def getevent(self):
out = self.lastevent
self.lastevent = {}
return out
if __name__ == '__main__':
w = mypygletwindow().winHandle
while not w.has_exit:
dt = pyglet.clock.tick()
w.dispatch_events()
w.clear()
# get events
e = w.getevent()
if e != {}:
print e
w.flip()
