Armin Ronacher added the comment: What it currently returns:
>>> from wsgiref.util import request_uri >>> request_uri({ ... 'wsgi.url_scheme': 'http', ... 'SCRIPT_NAME': '', ... 'PATH_INFO': '/\xe2\x98\x83', ... 'SERVER_PORT': '80', ... 'SERVER_NAME': 'localhost' ... }) 'http://localhost/%C3%A2%C2%98%C2%83' What it should return: 'http://localhost/%E2%98%83' ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue20138> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com