Armin Ronacher added the comment:

What it currently returns:

>>> from wsgiref.util import request_uri
>>> request_uri({
...  'wsgi.url_scheme': 'http',
...  'SCRIPT_NAME': '',
...  'PATH_INFO': '/\xe2\x98\x83',
...  'SERVER_PORT': '80',
...  'SERVER_NAME': 'localhost'
... })
'http://localhost/%C3%A2%C2%98%C2%83'

What it should return:

'http://localhost/%E2%98%83'

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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue20138>
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