Mark Dickinson <dicki...@gmail.com> added the comment:
> I am wondering whether int(sqrt(float(n))) can be used as a good initial > approximation. It can, but I'd prefer to avoid floating-point arithmetic (we don't have any guarantees about the accuracy of sqrt, so you'd always need a check and a fallback for the case where sqrt isn't accurate enough), and there are other purely-integer-based ways to produce a fast initial approximation. I do have some plans to add optimizations, but wanted to get the basic algorithm in first. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue36887> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
