Hi Chris Steve and you wrote:
>> there >> are times where I have really wanted to access the caller's environment, >> not the environment where my function was defined. > what am I missing? can't you get that by passing locals() in to a function? I think this will fail when values are changed. According to https://docs.python.org/3/library/functions.html#locals > The contents of this dictionary should not be modified; changes may not > affect the values of local and free variables used by the interpreter. I suspect that Jacob, the original poster, wants to change state, and also to read changed state. Jacob, could you confirm or correct, that you want the called function to be able to change state in caller (or perhaps even further up the stack). To finish, here's an interactive example of changing the value of locals(). >>> def f(a=1): loc = locals(); yield loc; yield a >>> it = f() >>> ctx = next(it) >>> ctx {'a': 1} ## This surprised me. >>> >>> >>> def f(a=1): loc = locals(); yield locals(); yield a >>> it = f() >>> ctx = next(it) >>> ctx {'a': 1, 'loc': {...}} >>> ctx['a'] = 3 >>> ctx['loc']['a'] = 5 >>> next(it) ## Is it 1 or 3 or 5? 1 ## The value of 'a' hasn't changed. -- Jonathan _______________________________________________ Python-ideas mailing list Python-ideas@python.org https://mail.python.org/mailman/listinfo/python-ideas Code of Conduct: http://python.org/psf/codeofconduct/
