17.12.20 21:58, Ethan Furman пише: > On 12/17/20 11:09 AM, Chris Angelico wrote: >> "a+b" is NOT implemented as "a.__add__(b)", nor as "type(a).__add__(b)"! > > Okay, what is it implemented as?
First, it can use not only method __add__ of the type of a, but also method __radd__ of the type of b. Second, the lookup of __add__ differs from both a.__add__ and type(a).__add__. It differs from a.__add__ because skips an instance dict and __getattr__. It differs from type(a).__add__ because does not fallback to methods of the metaclass. This all is pretty complicated. _______________________________________________ Python-ideas mailing list -- python-ideas@python.org To unsubscribe send an email to python-ideas-le...@python.org https://mail.python.org/mailman3/lists/python-ideas.python.org/ Message archived at https://mail.python.org/archives/list/python-ideas@python.org/message/ADK5DGEEPPFQ5XY55GUQWRUY3QBDXUSD/ Code of Conduct: http://python.org/psf/codeofconduct/
