On 26/08/2021 09:36, Marc-Andre Lemburg wrote:
In Python you can use a simple test for this:
I think you need math.isnan().
nan = float('nan')
l = [1,2,3,nan]
d = {nan:1, 2:3, 4:5, 5:nan}
s = set(l)
nan in l
True
That only works with identical nan-s, and because the container omits
the equality check for identical objects:
>>> nan = float("nan")
>>> nan in [nan]
True
But:
>>> nan == nan
False
>>> nan in [float("nan")]
False
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