On Mon, Oct 25, 2021 at 02:59:02PM +0100, Barry Scott wrote:
> def func(@y=x+1, @x=0):
>
> Is it unreasonable to get a UnboundLocal or SyntaxError for this case?
I think that UnboundLocalError is fine, if the caller doesn't supply x.
So all of these cases will succeed:
func(21, 20)
func(21, x=20)
func(y=21, x=20)
func(x=20, y=21)
func(x=20)
and I think that the only[1] case that fails is:
func()
An UnboundLocalError here is perfectly fine. That error is conceptually
the same as this:
def func():
y = x + 1
x = 0
and we don't try to make that a syntax error.
[1] To be pedantic, there are other cases like func(x=20, x=20) and
func(1, 2, 3, 4) that also fail. But you knew what I meant :-)
--
Steve
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