I can not break the original code in 2.4, if I try this:
import os, sys
class NoMimeError(Exception):
pass
def detectMimeType( filename ):
extension = filename[-3:]
basename = os.path.basename(filename)
if extension == "php":
return "application/x-php"
elif extension == "cpp" or extension.endswith("cc"):
return "text/x-c++-src"
elif extension == "1":
return 'BlahBlah'
elif extension == "2":
return 'BlahBlah'
elif extension == "3":
return 'BlahBlah'
elif extension == "4":
return 'BlahBlah'
elif extension == "5":
return 'BlahBlah'
elif extension == "6":
return 'BlahBlah'
elif extension == "7":
return 'BlahBlah'
elif extension == "8":
return 'BlahBlah'
elif extension == "9":
return 'BlahBlah'
elif extension == "10":
return 'BlahBlah'
elif extension == "11":
return 'BlahBlah'
elif extension == "12":
return 'BlahBlah'
elif extension == "13":
return 'BlahBlah'
elif extension == "14":
return 'BlahBlah'
elif extension == "15":
return 'BlahBlah'
elif extension == "16":
return 'BlahBlah'
elif extension == "17":
return 'BlahBlah'
elif extension == "18":
return 'BlahBlah'
elif extension == "19":
return 'BlahBlah'
elif extension == "20":
return 'BlahBlah'
elif extension == "xsl":
return "text/xsl"
elif basename.find( "Makefile" ) != -1:
return "text/x-makefile"
else:
raise NoMimeError
try:
print detectMimeType(r'c:\test.php')
print detectMimeType('c:\test.xsl')
print detectMimeType('c:\test.xxx')
except Exception, e:
print >> sys.stderr, '%s: %s' %(e.__class__.__name__, e)
I get
>>>
application/x-php
text/xsl
NoMimeError:
>>>
So although the dictionary solution is much nicer nothing seems wrong
with your code as it is - or am I missing something?
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