janama wrote: > Hi all, > > Using wx > When adding a second timer as i have the first, the second timer > adding stops the first timer (updating or stops?) . In this example im > updating a uptime and localtime label. It works fine for displaying the > last "self.startTimer2()" called. But prevents the previous > self.startTimer1() from running . Im doing something fundamentally > wrong i guess? > > def __init__(self, parent): > self._init_ctrls(parent) > > #Start timers > self.startTimer1() > self.startTimer2() > > def startTimer1(self): > self.t1 = wx.Timer(self) > self.t1.Start(360) # 360000 ms = 1/10 hour > self.Bind(wx.EVT_TIMER, self.OnUpTime) > > def startTimer2(self): > self.t2 = wx.Timer(self) > self.t2.Start(1000) # run every second > self.Bind(wx.EVT_TIMER, self.OnTime) > > def OnTime(self,evt): > self.lblTime.SetLabel(str(time.localtime())) > > def OnUpTime(self, evt): > self.lblUptime.SetLabel('Running ' + (str(myTimerText[0])) + ' > hours') # 1/10 hour count > myTimerText[0] = myTimerText[0] + .1 > > Any help appreciated, ta
The problem is not that the first timer ist stopped, the problem is that both timers happen to call the same method in the end. Think of the "Bind" method as an assignment: it assigns a handler function to an event source. If you call it twice for the same event source, the second call will overwrite the first event handler. That's what happens in your code. The easiest way to change this is by using different ids for the timers: def startTimer1(self): self.t1 = wx.Timer(self, id=1) self.t1.Start(2000) self.Bind(wx.EVT_TIMER, self.OnUpTime, id=1) def startTimer2(self): self.t2 = wx.Timer(self, id=2) self.t2.Start(1000) self.Bind(wx.EVT_TIMER, self.OnTime, id=2) This way, the timers launch two different events, which are bound to two different methods. -- http://mail.python.org/mailman/listinfo/python-list