Steven skrev: > For the purposes of this question, the list will be: > > t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] > > Now, I know that every 3rd element of the list belongs together: > > Group 1 = 0, 3, 6 > Group 2 = 1, 4, 7 > Group 3 = 2, 5, 8 > > I'm trying to sort this list out so that I get a list of lists > that contain the correct elements: > > Goal = [ [ "a", "n", "t"], [ "b", "a", "t"], > ["c", "a", "t" ] ]
#v+ >>> t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] >>> [t[i::3] for i in range(3)] [['a', 'n', 't'], ['b', 'a', 't'], ['c', 'a', 't']] >>> #v- Cheers, -- Klaus Alexander Seistrup SubZeroNet, Copenhagen, Denmark http://magnetic-ink.dk/ -- http://mail.python.org/mailman/listinfo/python-list