Steven wrote: > Hello everyone, > > I'm trying to work through a bit of a logic issue I'm having with a > script I'm writing. Essentially, I have a list that's returned to > me from another command that I need to regroup based on some aribitrary > length. > > For the purposes of this question, the list will be: > > t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] > > Now, I know that every 3rd element of the list belongs together: > > Group 1 = 0, 3, 6 > Group 2 = 1, 4, 7 > Group 3 = 2, 5, 8 > > I'm trying to sort this list out so that I get a list of lists that > contain the correct elements: > > Goal = [ [ "a", "n", "t"], [ "b", "a", "t"], > ["c", "a", "t" ] ] > > The actual data isn't as simple as this, but if I can get the logic > sorted out, I can handle the other part. > > Anyone have any good ideas on how to do this?
how about: >>> t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] >>> [t[i::3] for i in range(0,len(t)/3)] [['a', 'n', 't'], ['b', 'a', 't'], ['c', 'a', 't']] -- Bill Pursell -- http://mail.python.org/mailman/listinfo/python-list