[Nick Craig-Wood]

| Tim Golden <[EMAIL PROTECTED]> wrote:
| >          if os.path.isfile (filepath):
| >            print filepath
| 
| You might get a more accurate result using
| 
|   os.access(filepath, os.X_OK)
| 
| instead of
| 
|   os.path.isfile(filepath)
| 
| Which checks the file is executable

Sadly, not under Win32, hence the shenanigans with
the PATHEXT variable :)

TJG

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