Steve,
Yeah, in this particular application the ordering and reoccurrence of a value in a non-contiguous way does matter; if those two things weren't required I think the method you suggested would be a good way to remove the duplicates.
Thanks!
Coates, Steve (ACHE) wrote:
It's not _exactly_ what you asked for but it may be enough...
Python 2.4 (#60, Nov 30 2004, 11:49:19) [MSC v.1310 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information.
from sets import Set l = [0,0,1,1,1,2,2,3,3,3,2,2,2,4,4,4,5] s = Set(l) s
Set([0, 1, 2, 3, 4, 5])
l2 = list(s) l2
[0, 1, 2, 3, 4, 5]
I say it's not exactly what you wanted because I don't think the ordering of l2 is necessarily the same as l. That may or may not be a problem for you.
Regards Steve
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