Hi to all, I have a problem with a snippet of code that creates a Curl object
the code is c = pycurl.Curl() c.key = keyCurrent c.proxy = proxyCurrent c.url = "http://www.google."; + lg + "/search?hl=" + lg + "&q=" + c.key + "&meta=lr%3Dlang_" + lg + "&num=30" c.setopt(pycurl.URL, c.url) c.setopt(pycurl.PROXY, c.proxy) the last two lines raise a TypeError obviously proxyCurrent, lg and keyCurrent are parameters I noted that if I define c.proxy and c.url as costants e.g. c.url = "http://www.google.com/search?blah blah...." and c.proxy = "127.0.0.1:8080" it works However if I define them as described before pycurl raises the TypeError -- http://mail.python.org/mailman/listinfo/python-list
