On 8 Jun, 14:18, "Simon Brunning" <[EMAIL PROTECTED]> wrote: > On 6/7/07, Joe <[EMAIL PROTECTED]> wrote: > > > > > I have a list of lists that I would like to sort utilizing a certain index > > of the nested list. I am able to successfully use: > > > Import operator > > list = [["Apple", 1], ["airplane", 2]] > > list.sort(key=operator.itemgetter(0)) > > > But, unfortunately, this will be case sensitive (Apple will come before > > airplane because the A is capital) and I need it to be insensitive. > > Try: > > list.sort(key=lambda el: el[0].lower()) > > BUT - it's not a good idea to use list as a name, 'cos list is a > built-in, and you're obscuring it. > > -- > Cheers, > Simon B. > [EMAIL PROTECTED]://www.brunningonline.net/simon/blog/ > GTalk: simon.brunning | MSN: small_values | Yahoo: smallvalues
I have tried the following, for a one dimensional list and it works, but I can not get my head around this lambda. How would this be written, without the lamda ? mylist = ['Fred','bill','PAUL','albert'] mylist.sort(key=lambda el: el.lower()) Any pointer to an idiot's guide appreciated. Richard -- http://mail.python.org/mailman/listinfo/python-list
