[EMAIL PROTECTED] wrote:
> def f():
> a = 12
> def g():
> global a
> if a < 14:
> a=13
> g()
> return a
>
> print f()
>
> This function raises an error. Is there any way to access the a in
> f() from inside g().
Yes. Pass it to g when calling the latter and let g return the
result.
def f():
a = 12
def g(parm):
if parm < 14:
return 13
else:
return a
a = g(a)
return a
print f()
Strange refactoring though.
Regards,
Björn
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We are Microsoft. What you are experiencing is not a problem; it is
an undocumented feature.
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