[EMAIL PROTECTED] wrote:
> I have 2 lists of tuples that look like:
> E1=[('a','g'),('r','s')] and
> E2=[('g','a'),('r','q'),('f','h')].
> In this tuple, the ordering does not
> matter, i.e. (u,v) is the same as (v,u).
>
> What I want to do is the following:
> given 2 list of tuples, E1 and E2, I want to create another list with
> tuples that are common to both. So in the above example I would like
> to return ('a','g') as being common.
>
How about
>>> e1 = [('a', 'g'), ('r', 's')]
>>> e2 = [('g', 'a'), ('r', 'q'), ('f', 'h')]
>>> s2 = set(e2)
>>> s2.update((b, a) for (a, b) in e2)
>>> list(set(e1) & s2)
[('a', 'g')]
If you are on 2.3, continue to use Set instead of set and modify the update
line to use a list comprehension:
s2.update([(b, a) for (a, b) in e2])
Peter
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