[EMAIL PROTECTED] wrote:
> Consider the following:
>>>> a = {1:2, 3:4, 2:5}
>
> Say that i want to get the keys of a, sorted. First thing I tried:
>
>>>> b = a.keys().sort()
>>>> print b
> None
>
> Doesn't work. Probably because I am actually trying to sort the keys
> of the dictionary without copying them first. If that is the case,
> fine.
.sort returns None.
>>>> b = a.keys()
>>>> b.sort()
> [1, 2, 3]
This snippet is clearly edited, because .sort returns None:
>>> a = {1:2, 3:4, 2:5}
>>> b = a.keys()
>>> b.sort()
>>> b
[1, 2, 3]
The problem you're having here is that .sort returns None to indicate
that it mutates the object, rather than returning a new one. So get the
keys, sort them, and then move along.
> Works fine, but I would really like it if I could somehow do it in one
> line.
Why is doing it in one line a priority? Clarity is more important than
brevity.
Regardless, you can do it in one line with the sorted builtin:
>>> sorted(a.keys())
[1, 2, 3]
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Erik Max Francis && [EMAIL PROTECTED] && http://www.alcyone.com/max/
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