[EMAIL PROTECTED] wrote:
> Consider the following:
>
>>>>a = {1:2, 3:4, 2:5}
>
>
> Say that i want to get the keys of a, sorted. First thing I tried:
>
>
>>>>b = a.keys().sort()
>>>>print b
>
> None
>
> Doesn't work. Probably because I am actually trying to sort the keys
> of the dictionary without copying them first. If that is the case,
> fine. Next thing I do:
>
>
>>>>b = a.keys()
>>>>b.sort()
>
> [1, 2, 3]
>
> Works fine, but I would really like it if I could somehow do it in one
> line. As the problem seems to be copying the object, i try the
> following:
>
>
>>>>import copy
>>>>b = copy.copy(a.keys()).sort()
>>>>print b
>
> None
>
> Hmmm, why doesn't it work? Also,
>
>
>>>>b = copy.deepcopy(a.keys()).sort()
>>>>print b
>
> None
>
> (not that I thought that deepcopy will work since shallow didn't, I
> understand the difference :) )
> Obviously, I am missing something here. What am I thinking wrong? Why
> doesn't copying the object work?
> Thanks for all the help
>
sort() sorts a list in place and returns None. For a one-liner:
>>> a = {1:2, 3:4, 2:5}
>>> b = sorted(a.keys())
>>> b
[1, 2, 3]
Duncan
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