I need just the file name from a string containing the path to a file.  The 
name of the file starts with zeros.  This is problematic because the  lstrip 
function strips them leaving this as the result:
6128.jpg
 
 
How do I strip the path without losing the leading zeros in the file name?
 
―---------------------------------------------
import sys, os, win32com.client, string

teststring = 'C:\shoreline\dvd\prep area\800x\\006128.jpg'
print string.lstrip(teststring, 'C:\shoreline\dvd\prep area\800x\\')

-- 
http://mail.python.org/mailman/listinfo/python-list

Reply via email to