Hi, No, this won't do. What is needed is a way to yield the results of a generator from inside another generator with having to do a for-yield-loop inside the outter generator.
Regards, Francis Girard Le mardi 1 Mars 2005 22:35, Adam Przybyla a ÃcritÂ: > ÂÂÂÂÂÂÂÂ... mayby that way: > ython 2.2.3 (#1, Oct 15 2003, 23:33:35) > [GCC 3.3.1 20030930 (Red Hat Linux 3.3.1-6)] on linux2 > Type "help", "copyright", "credits" or "license" for more information. > > >>> from __future__ import generators > >>> def x(): > > ... Âfor i in range(10): yield i > ... > > >>> x() > > <generator object at 0x82414e0> > > >>> for k in x(): print k, > > ... > 0 1 2 3 4 5 6 7 8 9 > > >>> for k in x(): print k, > > ... > 0 1 2 3 4 5 6 7 8 9 > > >>> for k in x(): print k, > > ... > 0 1 2 3 4 5 6 7 8 9 > > >>> yield_all=[k for k in x()] > >>> yield_all > > [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] -- http://mail.python.org/mailman/listinfo/python-list
