Sorry, am getting this error.

>>> bigstring="python anaconda boa cobra"
>>> smallone="boa"
>>> smallone in bigstring
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: 'in <string>' requires character as left operand
>>> 
>>> if smallone in bigstring:
...    print 'ok'
... else:
...     print 'nok'
... 
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: 'in <string>' requires character as left operand

Do I need to import any module?

Thanks,
Ganesh
-----Original Message-----
From: Gary Herron [mailto:[EMAIL PROTECTED] 
Sent: 30 October 2007 12:09
To: Borse, Ganesh
Cc: python-list@python.org
Subject: Re: How to find if a string contains another string

Borse, Ganesh wrote:
> Hi,
>
> Am new to python.
> May someone please help me know this?
>
> How can we check whether one big string contains another small string?
>
> E.g. 
> bigstring="python anaconda boa cobra"
> smallone="boa"
>   
Use the operator named in:

>>> bigstring="python anaconda boa cobra"
>>> smallone="boa"
>>> smallone in bigstring
True

Often used in if statements like this:

>>> if smallone in bigstring:
...   print 'contained'
... else:
...   print 'not'
...
contained

Gary Herron

> If 0 == contains(bigstring,smallone):
>         print "Yes, boa is snake.."
>
> Is there any function like "contains" or "exists" in python?
> What are different alternatives we have?
>
> Please help.
>
> Thanks and Regards,
> Ganesh
>
> ======================================================================
> ======== Please access the attached hyperlink for an important 
> electronic communications disclaimer:
>
> http://www.credit-suisse.com/legal/en/disclaimer_email_ib.html
> ======================================================================
> ========
>
>   


==============================================================================
Please access the attached hyperlink for an important electronic communications 
disclaimer: 

http://www.credit-suisse.com/legal/en/disclaimer_email_ib.html
==============================================================================

-- 
http://mail.python.org/mailman/listinfo/python-list

Reply via email to