Hmm, how does this fare??
for i in range(len(a)):
if a[i]==99: a=a[:i]+a[i+1:]
I like following your guys code noodling. I can come up with something
that does what it appears your doing, sometimes, but as to it's relevant
merits I havent a clue :)
matt.
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Re:
Removal of element from list while
30/01/2008 13:04
traversing causes the next element to be
skipped
On Jan 30, 2008 6:57 AM, Arnaud Delobelle <[EMAIL PROTECTED]> wrote:
> Or one could use the trick of counting from the right (untested):
>
> n = len(a)
> for i, x in enumerate(a):
> if x == 99: del a[i-n]
Or one can put on his bellbottoms, horn-rimmed glasses, and wear a mullet:
i = 0
while i < len(a):
if a[i] == 99:
del a[i]
else:
i += 1
--
Neil Cerutti <[EMAIL PROTECTED]>
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