Christoph Zwerschke wrote: : Marc 'BlackJack' Rintsch schrieb: :: On Sun, 02 Mar 2008 14:15:09 +0000, Steve Turner wrote: :: ::: Apart from doing something like ::: a=[0,0,0] ::: b=[0,0,0] ::: c=[0,0,0] ::: d=[a,b,c] ::: ::: is there a better way of creating d?? :: :: a = [[0] * 3 for dummy in xrange(3)] : : Why not simply [[0]*3]*3 ?
I've just tried that and it gives the same as my earlier b=[a,a,a] -- Steve -- http://mail.python.org/mailman/listinfo/python-list