> >>> is there a better way of creating d?? > > >> a = [[0] * 3 for dummy in xrange(3)] > > Each element of a refers to a distinct array. > > > Why not simply [[0]*3]*3 ? > > All three elements of the result refer to the same array.
... whereas you reassign all three elements of [0]* 3. >>> ((0,)*3,)*3 ((0, 0, 0), (0, 0, 0), (0, 0, 0)) You're safe in this one-- changing [0][0] won't change [1][0], 'cuz you can't! -- http://mail.python.org/mailman/listinfo/python-list
