On May 12, 1:30 pm, John Machin <[EMAIL PROTECTED]> wrote: > Duncan Booth wrote: [...] > > I think the variant I came up with is a bit clearer: > > > for i in range(1,101): > > print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else 'Buzz') or i > > More than a bit clearer, IMO. How about > print ('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz') or i > (or perhaps > print (('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz')) or i > to save looking up the precedence rules) ?
Stuff clarity! How about for i in xrange(1, 101): print 'FizzBuzz'[4*(i%3>0):4+4*(i%5<1)] or i -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list