On May 12, 9:19 am, Guillermo <[EMAIL PROTECTED]> wrote: > Hi, > > This must be very basic, but how'd you pass the same *args several > levels deep? > > def func2(*args) > > print args # ((1, 2, 3),) > # i want this to output (1, 2, 3) as func1! > # there must be some better way than args[0]? > > def func1(*args): > > print args # (1, 2, 3) > func2(args) > > func1(1,2,3) > > Thanks! > > Guillermo
def func1(*args): print args func2(*args) # don't forget the '*' Matt -- http://mail.python.org/mailman/listinfo/python-list