On Tue, 02 Sep 2008 19:54:12 -0400, Derek Martin wrote:
>> And if they model an action there must be some way to activate the
>> action
>
> That's a reasonable assumption, but as I also said, the object might
> just describe the action -- essentially the equivalent of a struct in C.
``struct``\s in C describe *actions*!? Functions do this. And a class
that describes an action that is executed in the `__init__()` method is
conceptually a function and shouldn't be a class. There must be a better
name for the "thing" it returns. Again guideline, not law, but a very
strong guideline IMHO.
>> but the instances of `Popen` are no actions. There's no way to
>> "execute" a `Popen` instance.
>
> Yes there is... you execute it when you instantiate the object.
But then the instance itself isn't an action but the result of one.
> At the time of instantiation, you "open" the "P" (pipes). For an
> object which describes an action, I think it's perfectly sensible that
> instantiation is when the action occurs, […]
Here I disagree again. Because the type/class name of an instance should
be a name of the "thing"/concept of the instance, not the action used to
create it.
>> > Yet some of you state your case as if it is incontrovertable fact.
>> > I've given a good case as to why it IS a good name (one which I
>> > genuinely support), and disagree as you may, none of the points any
>> > of you have made invalidate or even weaken my argument.
>>
>> Maybe from your POV. Facts: It doesn't use the `popen()` function
>
> So? Neither does the C version of popen(), but that function is still
> called popen()!
Now you lost me. The C version of `popen()` isn't recursive, why on
earth should it be, so what's that statement supposed to mean!?
>> to three file objects, more attributes and methods), the function used
>> on Windows under the hood is called `CreateProcess()` not
>> `CreatePipe()`.
>
> How does Windows implement popen()? [I think they call it _popen()
> though...]
Doesn't matter because the `Popen()` implementation doesn't use `popen()`.
Ciao,
Marc 'BlackJack' Rintsch
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