Aaron "Castironpi" Brady a écrit :
On Oct 9, 3:48 am, Bruno Desthuilliers <bruno.
[EMAIL PROTECTED]> wrote:
Aaron "Castironpi" Brady a écrit :
Hello,
The 'inspect' module has this method:
inspect.getargvalues(frame)
It takes a frame and returns the parameters used to call it, including
the locals as defined in the frame, as shown.
def f( a, b, d= None, *c, **e ):
... import inspect
... return inspect.getargvalues( inspect.currentframe() )
...
f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )
(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
'e': {'h': 'g
hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
\Python26\lib\in
spect.pyc'>})
However, if you wanted a decorator that examines the parameters to a
function, you're out of luck. By the time you have a frame, you're
already in the function.
Hem...
def decorator(func):
def _decorator(*args, *kw):
print "func args are ", *args, **kw
return func(*args, **kw)
return _decorator
It is less of a problem without tuple unpacking, but you still have
code like:
if len( args )>= 2:
b= args[ 1 ]
else:
try:
b= (somehow check b's default val.)
except NoDefaultVal:
raise ArgumentError
Worse yet, you have it for each parameter. Unless I missed something,
this is the only way to mimic/recreate the signature of the decoratee.
I don't get what you're after ??? The decorator has full access to both
the actual params *and* the function's signature (via
inspect.getargspec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.currentframe(), but what ?
FWIW, Michele Simionato's decorator module has some trick to allow for
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a sane way.
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