En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi" Brady
<[EMAIL PROTECTED]> escribió:
On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
[EMAIL PROTECTED]> wrote:
I don't get what you're after ??? The decorator has full access to both
the actual params *and* the function's signature (via
inspect.getargspec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.currentframe(), but what ?
FWIW, Michele Simionato's decorator module has some trick to allow for
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a sane way.
It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs.
You are wrapping a function with this signature:
def f( a, b, c= None, *d, **e ):
You want to find out the values of 'a', 'b', and 'c' in a decorator.
You have these calls:
f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values
How do you determine 'a', 'b', and 'c'?
I'm afraid you'll have to duplicate the logic described here:
http://docs.python.org/reference/expressions.html#id9
To my knowledge, there is no available Python code (in the stdlib or
something) that already does that.
--
Gabriel Genellina
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