feb...@gmail.com a écrit :
#!/usr/bin/python
#Py3k, UTF-8
bank = int(input("How much money is in your account?\n>>"))
target = int(input("How much money would you like to earn each year?
\n>>"))
interest = 0
i = 0
while interest < target:
#determine the interest rate to use
if bank >= 9999:
rate = 0.006
elif bank >= 10000 and bank <= 24999:
rate = 0.0085
elif bank >= 25000 and bank <= 49999:
rate = 0.0124
elif bank >= 50000 and bank <= 99999:
rate = 0.0149
elif bank >= 100000:
rate = 0.0173
(snip)
I'm pretty certain that that is also the problem in the code. I'm
pretty sure it's a problem with the 'if' statements', and it looks
like it's one of those mistakes that's so simple you look back on it
and laugh at yourself. If you put in a bank number <= 9999, it fails,
saying "NameError: name 'rate' is not defined". If you put in one
higher, it runs correctly, but thinks that the rate is 0.006
Indeed. That's what you asked for. If bank is >= 9999, then rate will be
set to 0.006, and the following tests will be skipped. Else - since you
just don't handle the case -, rate is not defined at all.
I guess you wanted your first test to be:
if bank <= 9999:
...
FWIW, when using if/elif that way, make sure you always end with a
"default" else clause (even if just to signal you didn't expect to be
there...)
HTH
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