scsoce wrote:
I have a function return a reference, and want to assign to the
reference, simply like this:
>>def f(a)
return a
b = 0
* f( b ) = 1*
but the last line will be refused as "can't assign to function call".
In my thought , the assignment is very nature, but why the interpreter
refused to do that ?
Because, as in most languages, it's not even clear what you might mean
by this syntax. It doesn't have any meaning; assignments are made to
variables, not the results of function calls.
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