On Mon, Dec 29, 2008 at 1:01 AM, scsoce <scs...@gmail.com> wrote: > I have a function return a reference, and want to assign to the reference, > simply like this: >>>def f(a) > return a > b = 0 > * f( b ) = 1* > but the last line will be refused as "can't assign to function call". > In my thought , the assignment is very nature, but why the interpreter > refused to do that ?
Here's some links to help you better understand Python objects: http://effbot.org/zone/python-objects.htm http://effbot.org/zone/call-by-object.htm The second one is a bit denser reading, but it's important to learn that Python's approach to objects and "variables" is fundamentally different from that of C/C++. In the example below, there's no way in the Python language* that bar() can change the value of b, since strings and numbers are immutable. def foo(): b = 0 bar(b) print b # will always be 0 * There are stupid [ctypes/getframe/etc.] tricks, though I think all are implementation-specific -Miles -- http://mail.python.org/mailman/listinfo/python-list
